factorise :9(x+y)2 -16(x-3y)2
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2
Answer:
Let (2x−y)=p, then the equation 9(2x−y)
2
−4(2x−y)−13 becomes 9p
2
−4p−13
Consider the expression 9p
2
−4p−13 we can factorise it as follows:
9p
2
−4p−13=9p
2
+9p−13p−13=9p(p+1)−13(p+1)=(9p−13)(p+1)
Now, substitute the value of p as p=(2x−y):
(9p−13)(p+1)=(9(2x−y)−13)(2x−y+1)=(18x−9y−13)(2x−y+1)
Hence, 9(2x−y)
2
−4(2x−y)−13=(18x−9y−13)(2x−y+1)
Step-by-step explanation:
Answered by
1
Step-by-step explanation:
9(x+y) 2 - 16 (x-3y) 2
( 9x + 9y )2 - ( 16x - 48y )2
18x + 18y - ( 32x - 96y )
18x + 18y - 32x + 96y
-14x + 114y
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