factorise 9(x+y)^2-x^2
Answers
Answered by
210
9(x+y)^2-x^2
= {3 (x+y)}^2 -(x)^2
now, it is in the form of a^2 - b^2
so, by using that identity
{3 (x+y) -x}{3(x+y) + x}
= (3x + 3y - x) (3x + 3y +x)
= (2x + 3y )( 4x + 3y)
= {3 (x+y)}^2 -(x)^2
now, it is in the form of a^2 - b^2
so, by using that identity
{3 (x+y) -x}{3(x+y) + x}
= (3x + 3y - x) (3x + 3y +x)
= (2x + 3y )( 4x + 3y)
realsujaykumar:
thkq
you're welcome
Answered by
341
9(x+y)^2-x^2
=[ 3( x + y) ]^2 - x ^ 2
= [ 3( x + y) + x ] [ 3( x + y) - x ]
=[ 4x + 3 y ] [ 2x + 3y ]
Hope helped!
=[ 3( x + y) ]^2 - x ^ 2
= [ 3( x + y) + x ] [ 3( x + y) - x ]
=[ 4x + 3 y ] [ 2x + 3y ]
Hope helped!
Similar questions