Math, asked by OlympianSpawn, 6 months ago

Factorise : 92−42+4−2 / Expand: (5−3+)2/ Prove √5 is an irrational number. These are three questions, please answer them asap

Answers

Answered by guptauv21
2

Answer:

here's your answer

Step-by-step explanation:

92-46-2=92-48=44

(5-3)+2=4

√5=

Let

√5

be a rational number.

then it must be in form of

q

p

where, q

=0 ( p and q are co-prime)

√5

=

q

p

√5

×q=p

Suaring on both sides,

√5q

2

=p

2

--------------(1)

p

2

is divisible by√ 5.

So, p is divisible by√ 5.

p=√5c

Suaring on both sides,

p

2

=25c

2

--------------(2)

Put p

2

in eqn.(1)

√5q

2

=25(c)

2

q

2

=5c

2

So, q is divisible by √5.

.

Thus p and q have a common factor of √5.

So, there is a contradiction as per our assumption.

We have assumed p and q are co-prime but here they a common factor of √5.

The above statement contradicts our assumption.

Therefore,

√5 is an irrational number.

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