Question

Factorise:.........​

Answer 1

Answer:

Hope it's Helpful for you....

Answer 2

Question:

Factorise the following equation : $xy^8-yx^8$

Answer:

$xy(y-x)(y+x)(y^2+x^2)(y^4+x^4)$

Explanation:

So over you can see that Y and x is common in $xy^8-yx^8$.Let us take Y outside.

⇒$xy(x^9-y^9)$

⇒$xy[(y^4)^2-(x^4)^2]$        

You can see that it is there in formula of $[(a^2-b^2)=(a+b)(a-b)]$

So Now by using the formula you will get

⇒$xy(y^4-x^4)(y^4+x^4)$

Again you can make into the formula that is $[(a^2-b^2)=(a+b)(a-b)]$

⇒$xy[(y^2)^2-(x^2)^2](y^4-x^4)$

⇒$xy(y^2-x^2)(y^2+x^2)(y^2+x^2)$

⇒$xy(y-x)(y+x)(y^2+x^2)(y^4+x^4)$

Hence the final equation or answer is $xy(y-x)(y+x)(y^2+x^2)(y^4+x^4)$.