Question

Factorise 96abc (3a-12) (5b-30)÷144 (a-4) (b-6)

Answer 1

hope the solution in the picture helps

Answer 2

Answer:

10

Explanation:

Given

$\frac{[96abc(3a-12)(5b-30)]}{[144(a-4)(b-6)]}$

= $\frac{[16\times6\times3(a-4)\times5(b-6)]}{[16\times9\times(a-4)(b-6)]}$

After cancellation of (a-6) and (b-6), we get

= $\frac{16\times3\times2\times3\times5}{16\times3\times3}$

= $(2\times5)$

=$10$

Therefore,

$\frac{[96abc(3a-12)(5b-30)]}{[144(a-4)(b-6)]}$

= 10

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