Question

factorise :→
(99)³??​

Answer 1

Answer:

We have,

(99)

3

=(100−1)

3

We know that

(a−b)

3

=a

3

−b

3

−3ab(a−b)

Therefore,

=(100)

3

−1

3

−3×100×1×(100−1)

=1000000−1−300(100−1)

=1000000−1−30000+300

=970299

Hence, this is the answer.

Step-by-step explanation:

We have,

(99)

3

=(100−1)

3

We know that

(a−b)

3

=a

3

−b

3

−3ab(a−b)

Therefore,

=(100)

3

−1

3

−3×100×1×(100−1)

=1000000−1−300(100−1)

=1000000−1−30000+300

=970299

Hence, this is the answer.

Answer 2

$\huge\mathtt\pink{Answer}</p><p>$

(a-b)³= a³-b³-3ab(a-b)

(99)³=(100-1)³

(99)³=1000000-1-300(100-1)

(99)³=1000000-1-29700

(99)³=970299

I hope it will help you ✌️