Math, asked by sangam06, 9 months ago

factorise: 9a^2+1/9a^2-18

Answers

Answered by gautam2406

4

Step-by-step explanation:

9a^2+1/9 a^2-18

=(3a)^2+(1a/3)^2+2×3a×1a/3-18-6

(3a+1a/3)^2-24

Answered by Anonymous

3

Answer:

Hey mate please refer to the attachment

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