Question

factorise: 9a^2+1/9a^2-18​

Answer 1

Step-by-step explanation:

9a^2+1/9 a^2-18

=(3a)^2+(1a/3)^2+2×3a×1a/3-18-6

(3a+1a/3)^2-24

Answer 2

Answer:

Hey mate please refer to the attachment