factorise 9a^2+4b^2+16c^2+12ab-16bc-24ca
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0
Answer:
x(y
2
−z
2
)+y(z
2
−x
2
)+z(x
2
−y
2
)=xy
2
−xz
2
+yz
2
−yx
2
+zx
2
−zy
2
Arrange the terms in descending order of power of x.
=−x
2
y+zx
2
+xy
2
−xz
2
−y
z
+yz
2
=−x
2
(y−z)+x(y
2
−z
2
)−yz(y−z)
=−x
2
(y−z)+x(y−z)(y+z)−yz(y−z)
=(y−z)[−x
2
+x(y+z)−yz]
(y−z)[−x
2
+xy+xz−yz]
Arrange the term in bracket in descending order of the power of y.
=(y−z)[xy−yz−x
2
+xz]
=(y−z)[−y(−x+z)+x(−x+z)]
=(x−y)(y−z)(z−x).
Answered by
0
Answer:
9a²+4b²+16c²+12ab-16bc-24ca
Step-by-step explanation:
hope it helpful
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