Question

factorise 9a^2+4b^2+25c^2-12ab-20abc+30ac​

Answer 1

Step-by-step explanation:

$9a^2+4b^2+25c^2-12ab-20bc+30ac \\ \\ {(3a)}^{2} + {(2b)}^{2} + {(5c)}^{2} - 2(3a)(2b) - 2(2b)(5c) + 2(3a)(5c) \\ \\ {(3a)}^{2} + {( - 2b)}^{2} + {(5c)}^{2} + 2(3a)( - 2b) + 2( - 2b)(5c) + 2(3a)(5c) \\ \\ = {(3a - 2b + 5c)}^{2} \\ \\ wkt \\ \\ (x + y + z) {}^{2} = {x}^{2} + {y}^{2} + {z}^{2} + 2xy + 2yz + 2zx$

hope it helps