Question

Factorise : 9a
2–9b2 + 6a + 1​

Answer 1

Step-by-step explanation:

Given Equation is 9a^2-9b^2+6a+1.

It can be written as :

9a^ 2+6a+1-9b^2

(3a+1)^ 2-(3b)^2

We know that a^2-b^2=(a+b) (a-b)

(3a+1+3b) (3a+1-3b) .

Hope this help you