Factorise 9a^2 -(a^2-4)^2
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9a² - (a² - 4)²
= (3a)² - (a²-4)²
Using a² - b² = (a-b)(a+b)
= [3a - (a² - 2²)] [3a + (a² - 2²)]
= (3a - a² + 2²) [3a + (a-2)(a+2)]
= [3a + (2² - a²)] [3a + (a-2)(a+2)]
= [3a + (2-a)(2+a)] [3a + (a-2)(a+2)]
= (3a)² - (a²-4)²
Using a² - b² = (a-b)(a+b)
= [3a - (a² - 2²)] [3a + (a² - 2²)]
= (3a - a² + 2²) [3a + (a-2)(a+2)]
= [3a + (2² - a²)] [3a + (a-2)(a+2)]
= [3a + (2-a)(2+a)] [3a + (a-2)(a+2)]
abbs98:
not the answer
then what is ans?
we
what?
I can't send the answer
some problem I think
a+4 X a-1 X 4-a X 1+a
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