Question

Factorise: 9a^2b-24ab^2+16b^3
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Answer 1

Answer:

b(3a−4b)(3a−4b)

Step-by-step explanation:

9a2b−24ab2+16b3

9a2b−24ab2+16b3

=b(3a−4b)(3a−4b)

Answer 2

Answer:

$Rewrite 9a29a2 as (3a)2(3a)2.</p><p></p><p>(3a)2+24ab+16b2(3a)2+24ab+16b2</p><p></p><p>Rewrite 16b216b2 as (4b)2(4b)2.</p><p></p><p>(3a)2+24ab+(4b)2(3a)2+24ab+(4b)2</p><p></p><p>Check that the middle term is two times the product of the numbers being squared in the first term and third term.</p><p></p><p>$

Rewrite

9

a

2

as

(

3

a

)

2

.

(

3

a

)

2

+

24

a

b

+

16

b

2

Rewrite

16

b

2

as

(

4

b

)

2

.

(

3

a

)

2

+

24

a

b

+

(

4

b

)

2

Check that the middle term is two times the product of the numbers being squared in the first term and third term.