Math, asked by STVENIKA987, 3 months ago

Factorise 9a^4+4b^4-13a^2b^2

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Answers

Answered by mrittika3278
2

Answer:

(3a+2b)(3a−2b)(a+b)(a−b)

Step-by-step explanation:

Hi friend!

9a^4 + 4b^4 − 13a^2b^2

Step 1-

Write in the standard form

=9a^4−13a^2b^2+4b^4

Step 2 -

Break the expression into groups:-------

=(9a^4−4a^2b^2)+(−9a^2b^2+4b^4)

Factor out a^2 from 9a^4−4a^^2b2:    

a^2(9a^2−4b^2)

Factor out −b^2 from −9a^2b^2+4b^4:  

 −b^2(9a^2−4b^2)

=a^2(9a^2−4b^2)−b^2(9a^2−4b^2)

Step3 -

Factor out common term 9a^2−4b^2

=(9a^2−4b^2)(a^2−b^2)

Factor 9a^2−4b^2:    (3a+2b)(3a−2b)

=(3a+2b)(3a−2b)(a2−b2)

Step 4-

Factor a^2−b^2:    (a+b)(a−b)

=(3a+2b)(3a−2b)(a+b)(a−b)

Hope this helps you! Do mark me the brainliest!

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