Factorise 9a^4+4b^4-13a^2b^2
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Answer:
(3a+2b)(3a−2b)(a+b)(a−b)
Step-by-step explanation:
Hi friend!
9a^4 + 4b^4 − 13a^2b^2
Step 1-
Write in the standard form
=9a^4−13a^2b^2+4b^4
Step 2 -
Break the expression into groups:-------
=(9a^4−4a^2b^2)+(−9a^2b^2+4b^4)
Factor out a^2 from 9a^4−4a^^2b2:
a^2(9a^2−4b^2)
Factor out −b^2 from −9a^2b^2+4b^4:
−b^2(9a^2−4b^2)
=a^2(9a^2−4b^2)−b^2(9a^2−4b^2)
Step3 -
Factor out common term 9a^2−4b^2
=(9a^2−4b^2)(a^2−b^2)
Factor 9a^2−4b^2: (3a+2b)(3a−2b)
=(3a+2b)(3a−2b)(a2−b2)
Step 4-
Factor a^2−b^2: (a+b)(a−b)
=(3a+2b)(3a−2b)(a+b)(a−b)
Hope this helps you! Do mark me the brainliest!
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