Question

Factorise 9a square+4b square+16c square 12ab - 16bc-24ca

Answer 1

Step-by-step explanation:

ANSWER

9a

2

+4b

2

+16c

2

+2ab−16bc−24ca

= (3a)

2

+(2b)

2

+(−4c)

2

+2(3a)(2b)+2(2b)(−4c)+2(−4c)(2a)

Suitable identities is (x+y+z)

3

=x

3

+y

3

+z

3

+2xy+2yz+2xz

Therefore, (3a)

2

+(2b)

2

+(−4c)

2

+2(3a)(2b)+2(2b)(−4c)+2(−4c)(2a)

= (3a+2b−4c)

2