Question

factorise 9a square + 4b square + c square + 12 ab - 4bc - 6 ac

Answer 1

Answer:

(a+b-c)^2= a^2+b^2+c^2+2ab+2bc-2ac

9a^2+4b^2+c^2+12ab-4b-6ac=  (3a+2b-c)^2

(3a+2b-c)^2