Question

factorise 9a²-4(b-c)²​

Answer 1

Answer:

$9 {a}^{2} - 4 {(b - c)}^{2} \\ \\ = {(3a)}^{2} - {(2b - 2c)}^{2} \\ \\ = (3a - (2b- 2c))(3a + 2b - 2c) \\ \\ = (3a - 2b + 2c)(3a + 2b - 2c)$

Answer 2

Answer:

9 a ² - 4 ( b - c ) ²

9a² - 4 ( b² - 2bc + c² )

9a² -4b² +8bc -4c²

Step-by-step explanation:

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