Question

: Factorise
9a² +6ab + b²​

Answer 1

Given

Factorise

9a² +6ab + b²

Solution

Applying identity to solve this Factorise

(a + b)² = a² + 2ab + b²

= 9a² + 6ab + b²

= (3a)² + 2 × 3a × b + (b)²

= (3a + b)²

= (3a + b)(3a + b)

Some important identities

• (a+b)² = a² + b² +2ab
• (a-b)² = a² + b² - 2ab
• (a+b)³ = a³ + b³ + 3ab(a+b)
• (a-b)³ = a³ -b³ - 3ab(a-b)
• a² - b² = (a+b)(a-b)
• a³ + b³ = (a+b)(a² - ab +b²)
• a³ - b³ = (a-b)(a² + ab +b²)

Answer 2

Answer:

as we use (a+b)2

Step-by-step explanation:

plz mark as brain list