Question

Factorise: 9a4b3+15a3b2-3a2b​

Answer 1

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(3a-2b)³+(2b-c)³+(c-3a)³

Since,

(3a-2b)+(2b-c)+(c-3a) = 0

Therefore,

(3a-2b)³+(2b-c)³+(c-3a)³

= 3(3a-2b)(2b-c)(c-3a) Source(s): If a+b+c = 0

Then,

a + b = - c

Cubing Both Sides.

(a+b)³ = - c³

a³ + b³ + 3a^2b + 3ab² = - c³

a³ + b³ = - c³ - 3ab ( a + b )

a³ + b³ + c³ = - 3abc ( Because a+b=-c )