Math, asked by monishzishan, 11 months ago

factorise=9p^4-24p^2q^2+16q^2-256r^2

Answers

Answered by mysticd
12

Answer:

(3p²-4q²+16r)(3p²-4q²-16r)

Step-by-step explanation:

It may be like this,

9p-24p²q²+16q-256r²

= [(3p²)²-2×3p²×4q²+(4q²)²]-256r²

/* By algebraic identity:

-2xy+ = (x-y)² */

= (3p²-4q²)² - (16r)²

= [(3p²-4q²)+16r][(3p²-4q²)-16r]

=(3p²-4q²+16r)(3p²-4q²-16r)

Answered by jayantkora7
7

(3p2-4p2+16r)^2......,..

Step-by-step explanation:

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