factorise=9p^4-24p^2q^2+16q^2-256r^2
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Answered by
12
Answer:
(3p²-4q²+16r)(3p²-4q²-16r)
Step-by-step explanation:
It may be like this,
9p⁴-24p²q²+16q⁴-256r²
= [(3p²)²-2×3p²×4q²+(4q²)²]-256r²
/* By algebraic identity:
x²-2xy+y² = (x-y)² */
= (3p²-4q²)² - (16r)²
= [(3p²-4q²)+16r][(3p²-4q²)-16r]
=(3p²-4q²+16r)(3p²-4q²-16r)
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Answered by
7
(3p2-4p2+16r)^2......,..
Step-by-step explanation:
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