Factorise : 9x^2-1/16
Answers
Answered by
22
It's simple :
9x^2 - 1/16
3x^2 - (1/4)^2
We know that a^2 - b^2 = (a+b)(a-b)
(3x + 1/4)(3x - 1/4).
9x^2 - 1/16
3x^2 - (1/4)^2
We know that a^2 - b^2 = (a+b)(a-b)
(3x + 1/4)(3x - 1/4).
siddhartharao77:
Sorry i thought its 9x^2 - 16.
It's simple :
9x^2 - 1/16
3x^2 - (1/4)^2
We know that a^2 - b^2 = (a+b)(a-b)
(3x + 1/4)(3x - 1/4).
9x^2 - 1/16
3x^2 - (1/4)^2
We know that a^2 - b^2 = (a+b)(a-b)
(3x + 1/4)(3x - 1/4).
Thanks
I have sent the answer for correction. Please do the necessary corrections
I have corrected it.Thanks riya
thanks jyothi for the brainliest
Answered by
3
Answer: is
(3x+1/4) (3x-1/4)
Step-by-step explanation:
9x²-1/16
=(3x)²-(1/4)²
Using Identity [ a²-b²=(a+b)(a-b) ]
=(3x+1/4) (3x-1/4)
I hope my answer satisfy you.
THANK YOU.
Similar questions