Factorise 9x^2 + 2 + 1/9x^2
Answers
Answered by
3
We have to factorise the given polynomial.
We can write it as:
We know that:
Therefore, the polynomial becomes:
★ Hence, the factorisation of the given polynomial is (3x + 1/3x)²
- (a + b)² = a² + 2ab + b²
- (a - b)² = a² - 2ab + b²
- a² - b² = (a + b)(a - b)
- (a + b)³ = a³ + 3ab(a + b) + b³
- (a - b)³ = a³ - 3ab(a - b) - b³
- a³ + b³ = (a + b)(a² - ab + b²)
- a³ - b³ = (a - b)(a² + ab + b²)
- (x + a)(x + b) = x² + (a + b)x + ab
- (x + a)(x - b) = x² + (a - b)x - ab
- (x - a)(x + b) = x² - (a - b)x - ab
- (x - a)(x - b) = x² - (a + b)x + ab
anindyaadhikari13:
Thanks for the Brainliest :)
Answered by
1
Answer:
How to solve your problem
9 2 + 2 + 1 9 ⋅ 2
Step-by-step explanation:
9
2
+
2
+
1
9
2
9x^{2}+2+\frac{1}{9}x^{2}
9x2+2+91x2
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