Question

FACTORISE : 9x^2-22x+8

Answer 1

9x²-22x+8
9x²-18x-4x+8
9x(x-2)-4(x-2)
(x-2)(9x-4)

Answer 2

Answer:

$9x^2-22x+8=(x-2)(9x-4)$    

Step-by-step explanation:

Given : Expression $9x^2-22x+8$

To find : Factorise the given expression?

Solution :

The solution of a quadratic equation $ax^2+bx+c=0$ is

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

On comparing with $9x^2-22x+8=0$

a=9 , b=-22, c=8

Substitute the values in the solution,

$x=\frac{-(-22)\pm\sqrt{(-22)^2-4(9)(8)}}{2(9)}$

$x=\frac{22\pm\sqrt{484-288}}{18}$

$x=\frac{22\pm\sqrt{196}}{18}$

$x=\frac{22\pm 14}{18}$

$x=\frac{11\pm 7}{9}$

$x=\frac{11+7}{9},\frac{11-7}{9}$

$x=\frac{18}{9},\frac{4}{9}$

$x=2,0.44$

Therefore, The value of x is 2,0.44.

Factorise form is $9x^2-22x+8=(x-2)(9x-4)$