Question

Factorise 9x^2-22x+8
Thanks in advance

Answer 1

9x^2-22x+8
=9x^2-18x-4x+8
=9x (x-2)-4 (x-2)
=(9x-4) (x-2)

Answer 2

$\sf\blue{\underline{\underline{\: \: Answer : \: }}}$

The Given Expression is 9x² - 22x + 8.

Here,

9 × 8 = 72

So,

we try to split -22 into two parts whose sum is -22 and product 72.

Clearly, (-18) + (-4) = -22 and (-18) × (-4) = 72

$\longrightarrow\sf{ 9x^2 - 22x + 8} \\ \longrightarrow\sf{9x^2 - 18x - 4x + 8} \\ \longrightarrow\sf{ 9x(x-2) -4(x-2)} \\ \longrightarrow\sf{(x-2)(9x-4)}$

Hence,

$\sf\red{(x-2)(9x-4)}$ is the factors.