Factorise 9x^2- (3y + z)^2
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Step-by-step explanation:
We know that, a^2 + b^2 = ( a + b ) ( a - b )
Here, 9x^2- (3y + z)^2
= [ 9x + ( 3y + z ) ] [ 9x - ( 3y + z ) ]
= ( 9x + 3y + z ) ( 9x - 3y - z ) .
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