Factorise :- 9x^2-64
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Answered by
5
9x^2-64=(3x)^2-(8)^2
a^2-b^2 =(a+b)(a-b)
(3x+8)(3x-8)
Answered by
2
Step-by-step explanation:
9x² - 64
=(3x)² - (8)²
Now we will use the identity a² - b² = (a-b)(a+b)
So according to the identity-
(3x-8)(3x+8)
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