factorise 9x^2-6b^2x-(a^4-b^4)=0
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Solution :
∴ 9x² - 6b²x - (a⁴ - b⁴)
= 9x² - 6b²x + b⁴ - a⁴
= {(3x)² - (2 * 3x * b²) + (b²)²} - (a²)²
= (3x - b²)² - (a²)²
= (3x - b² + a²) (3x - b² - a²) ,
which is the required factorization.
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