Question

factorise:9x^2-6xy+y^2-z^2​

Answer 1

Step-by-step explanation:

By using the identity:-(a+b)²

that is (a)²+2ab+(b)²

so,(3x)²-2×3x × y+(y)²-z²

(3x-y)² - (z)²

by using identity:- a²-b²

so we get,(3x-y+z) (3x-y-z)

I hope this is helpful to you.......