factorise 9x^2+y^2+z^2-6xy+2yz-2xz,x=1,y=2,z=-1
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9x^2+y^2+z^2-6xy+2yz-2zx
= (3x)^2+(-y)^2+(-z)^2+2×(3x)×(-y)+2×(-y)×(-z)+2×(-z)×(3x)
=(3x-y-z)^2
as (a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
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Here's your answer...
9x^2+y^2+z^2-6xy+2yz-2zx
= (3x)^2+(-y)^2+(-z)^2+2×(3x)×(-y)+2×(-y)×(-z)+2×(-z)×(3x)
=(3x-y-z)^2
as (a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
[0111001100]... More questions detected...[010010111100]
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