Question

factorise 9x2+49y2-42xy-30xz+70yz​

Answer 1

Step-by-step explanation:

the question should be

9x²+49y²-42xy-30xz+70yz + 25z²

if so then....

(3x)² + (7y)² + (5z)² - 2(3x)(7y) -(2)(3x)(5z) + (2)(7y)(5z)

as the negative sign is with x variable, therefore

=> (-3x)² + (7y)² + (5z)² + 2(-3x)(7y) + (2)(-3x)(5z) + (2)(7y)(5z)

= (-3x+7y+5z) (-3x +7y +5z)

Answer 2

Answer:

9x²+49y²-42xy-30xz+70yz + 25z²

if so then....

(3x)² + (7y)² + (5z)² - 2(3x)(7y) -(2)(3x)(5z) + (2)(7y)(5z)

as the negative sign is with x variable, therefore

=> (-3x)² + (7y)² + (5z)² + 2(-3x)(7y) + (2)(-3x)(5z) ++ (2)(7y)(5z)

= (-3x+7y+5z) (-3x +7y +5z)

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