Math, asked by robin6111, 11 months ago

factorise 9x2+ 6x+1​

Answers

Answered by Anonymous
18

9x² + 6x + 1

=>9x² + 3x + 3x + 1

=>3x(3x + 1) + 1(3x + 1)

=> (3x+1)(3x+1)

Answered by babushall
1

Step-by-step explanation:

Factoring  9x2+6x+1 

The first term is,  9x2  its coefficient is  9 .

The middle term is,  +6x  its coefficient is  6 .

The last term, "the constant", is  +1 

Step-1 : Multiply the coefficient of the first term by the constant   9 • 1 = 9 

Step-2 : Find two factors of  9  whose sum equals the coefficient of the middle term, which is   6 .

  3   +   3   =   6   That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  3  and  3 

                     9x2 + 3x + 3x + 1

Step-4 : Add up the first 2 terms, pulling out like factors :

                    3x • (3x+1)

              Add up the last 2 terms, pulling out common factors :

                     1 • (3x+1)

Step-5 : Add up the four terms of step 4 :

                    (3x+1)  •  (3x+1)

             Which is the desired factorization

(3x+1)(3x+1)=0.

(3x+1) = 0 or (3x+1) = 0.

3x= -1 or 3x = -1.

x = -1/3 or x = -1/3 .

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