factorise 9x2+ 6x+1
Answers
9x² + 6x + 1
=>9x² + 3x + 3x + 1
=>3x(3x + 1) + 1(3x + 1)
=> (3x+1)(3x+1)
Step-by-step explanation:
Factoring 9x2+6x+1
The first term is, 9x2 its coefficient is 9 .
The middle term is, +6x its coefficient is 6 .
The last term, "the constant", is +1
Step-1 : Multiply the coefficient of the first term by the constant 9 • 1 = 9
Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is 6 .
3 + 3 = 6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 3
9x2 + 3x + 3x + 1
Step-4 : Add up the first 2 terms, pulling out like factors :
3x • (3x+1)
Add up the last 2 terms, pulling out common factors :
1 • (3x+1)
Step-5 : Add up the four terms of step 4 :
(3x+1) • (3x+1)
Which is the desired factorization
(3x+1)(3x+1)=0.
(3x+1) = 0 or (3x+1) = 0.
3x= -1 or 3x = -1.
x = -1/3 or x = -1/3 .