factorise (9y*+25z*+15yz)
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Step-by-step explanation:
Since we have given that
4x^2+9y^2-25x^2+12xy4x
2
+9y
2
−25x
2
+12xy
We need to find the factorisation:
\begin{gathered}(4x^2+9y^2+12xy)-25z^2\\\\Using\ (a+b)^2=a^2+b^2+2ab\\\\=(2x)^2+(3y)^2+2\times 2x\times 3y-(5z)^2\\\\=(2x+3y)^2-(5z)^2\\\\Using\ a^2-b^2=(a-b)(a+b)\\\\=(2x+3y-5z)(2x+3y+5z)\end{gathered}
(4x
2
+9y
2
+12xy)−25z
2
Using (a+b)
2
=a
2
+b
2
+2ab
=(2x)
2
+(3y)
2
+2×2x×3y−(5z)
2
=(2x+3y)
2
−(5z)
2
Using a
2
−b
2
=(a−b)(a+b)
=(2x+3y−5z)(2x+3y+5z)
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