Math, asked by mohan9774, 5 months ago

Factorise 9y2 – 12y +4 with solution​

Answers

Answered by anindyaadhikari13
3

Required Answer:-

Given to factorise:

  • 9y² - 12y + 4

Solution:

We have,

9y² - 12y + 4

= 9y² - 6y - 6y + 4

= 3y(3y - 2) - 2(3y - 2)

= (3y - 2)(3y - 2)

= (3y - 2)²

Hence, the factorised form of the polynomial is (3y - 2)²

Alternative way,

We have,

9y² - 12y + 4

= (3y)² - 2 × 3y × 2 + (2)² [In a² - 2ab + b² form]

= (3y - 2)² [(a - b)² = a² - 2ab + b²]

Hence, the factorised form of the given polynomial is (3y - 2)²

Answer:

  • Factorised form:- (3y - 2)²
Answered by Anonymous
82

\huge\sf\underline\blue{☆Solution☆}

Given 9y²-12y + 4

9 × 4 = 36

36 factors

1× 36

2 × 18

3 × 6

4 × 9

6 × 6( or) -6 × -6

9 × 4

18 × 2

36 × 1

Here sum should be -12 So, -6-6 = -12

So split middle term -6y -6y

9y² -6y -6y + 4

3y(3y-2)-2(3y-2)

(3y-2) ( 3y -2)

(3y-2)² is the answer fir 9y² -12y + 4

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