Question

Factorise 9y2 + 4z2 - 12zy using identities.​

Answer 1

Answer:

Step-by-step explanation:The factorisation of 4x^{2} +12xy+9y^{2}4x

2

+12xy+9y

2

is"(2x+3y)(2x+3y)"."(2x+3y)(2x+3y)".

Step-by-step explanation:

We have,

4x^{2} +12xy+9y^{2}4x

2

+12xy+9y

2

To find, the factorisation of 4x^{2} +12xy+9y^{2}4x

2

+12xy+9y

2

= ?

= (2x)^{2} +2(2x)(3y)+(3y)^{2}(2x)

2

+2(2x)(3y)+(3y)

2

=(2x+3y)^{2}=(2x+3y)

2

=(2x+3y)(2x+3y)=(2x+3y)(2x+3y)

[∵ (a+b)^{2} =a^{2} +2ab+b^{2}(a+b)

2

=a

2

+2ab+b

2

Hence, the factorisation of 4x^{2} +12xy+9y^{2}4x

2

+12xy+9y

2

is (2x+3y)(2x+3y).(2x+3y)(2x+3y).

Answer 2

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