factorise a 12 x 4 - 4 x 12
Answers
Answered by
10
A¹².y⁴ - a⁴.y¹²
you can write a¹² = a⁴.a^8
again, y¹² = y⁴.y^8
now use this,
= a⁴.a^8.y⁴ - a⁴.y⁴.y^8
you see that a⁴.y⁴ are common terms in both so,
= a⁴.y⁴( a^8 - y^8)
[ use,formula , x² - y² = (x - y)(x + y) ]
= a⁴.y⁴(a⁴ - y⁴)(a⁴ + y⁴)
=a⁴.y⁴(a² - y²)(a² + y²)(a⁴+y⁴)
=a⁴.y⁴(a - y)(a+ y)(a²+y²)(a⁴ + y⁴)
you can write a¹² = a⁴.a^8
again, y¹² = y⁴.y^8
now use this,
= a⁴.a^8.y⁴ - a⁴.y⁴.y^8
you see that a⁴.y⁴ are common terms in both so,
= a⁴.y⁴( a^8 - y^8)
[ use,formula , x² - y² = (x - y)(x + y) ]
= a⁴.y⁴(a⁴ - y⁴)(a⁴ + y⁴)
=a⁴.y⁴(a² - y²)(a² + y²)(a⁴+y⁴)
=a⁴.y⁴(a - y)(a+ y)(a²+y²)(a⁴ + y⁴)
Answered by
15
HEY MATE.....!
HERE'S THE ANSWER...
To factorise: 12 x 4 - 4 x 12
= 4( 12 x 1 - 1 x 12)
= 4 x ( 12 -12)
= 4 x 0
HOPE IT HELPS
THANK YOU
-SHIVAMSHAURYA
HERE'S THE ANSWER...
To factorise: 12 x 4 - 4 x 12
= 4( 12 x 1 - 1 x 12)
= 4 x ( 12 -12)
= 4 x 0
HOPE IT HELPS
THANK YOU
-SHIVAMSHAURYA
shivamshaurya:
mark me as brainliest
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