Question

factorise a^2-1+2b-b^2​

Answer 1

Answer:

The required factors: (a + b - 1)(a - b + 1)

Step-by-step explanation:

Given that,

$a^{2}-1+2b-b^{2}\\=a^{2}-(1-2b+b^{2})\\=(a)^{2}-[(1)^{2}-2.1.b+(b)^{2}]\\=(a)^{2}-(b-1)^{2}\\=(a+b-1)(a-b+1)$

∴$a^{2}-1+2b-b^{2}=(a+b-1)(a-b+1)$

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