Question

factorise (a^2)-1/(b^2)

Answer 1

Step-by-step explanation:

HI

Solution:

Solution:a^2-1-2b-b^2

Solution:a^2-1-2b-b^2a^2-(1+2b+b^2)

Solution:a^2-1-2b-b^2a^2-(1+2b+b^2)Using identity : (x+y)^2=x^2+y^2+2xy

Solution:a^2-1-2b-b^2a^2-(1+2b+b^2)Using identity : (x+y)^2=x^2+y^2+2xya^2-(1+2b+b^2)

Solution:a^2-1-2b-b^2a^2-(1+2b+b^2)Using identity : (x+y)^2=x^2+y^2+2xya^2-(1+2b+b^2)a^2-(1^2+2b+b^2)

Solution:a^2-1-2b-b^2a^2-(1+2b+b^2)Using identity : (x+y)^2=x^2+y^2+2xya^2-(1+2b+b^2)a^2-(1^2+2b+b^2)a^2-(b+1)^2

Solution:a^2-1-2b-b^2a^2-(1+2b+b^2)Using identity : (x+y)^2=x^2+y^2+2xya^2-(1+2b+b^2)a^2-(1^2+2b+b^2)a^2-(b+1)^2Using identity : a^2-b^2=(a+b)(a-b)

Solution:a^2-1-2b-b^2a^2-(1+2b+b^2)Using identity : (x+y)^2=x^2+y^2+2xya^2-(1+2b+b^2)a^2-(1^2+2b+b^2)a^2-(b+1)^2Using identity : a^2-b^2=(a+b)(a-b)(a+b+1)(a-b-1)

Solution:a^2-1-2b-b^2a^2-(1+2b+b^2)Using identity : (x+y)^2=x^2+y^2+2xya^2-(1+2b+b^2)a^2-(1^2+2b+b^2)a^2-(b+1)^2Using identity : a^2-b^2=(a+b)(a-b)(a+b+1)(a-b-1)Hence a^2-1-2b-b^2 = (a+b+1)(a-b-1)

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