Math, asked by sargun49, 3 months ago

factorise:a^2-14a-15( really really urgent)

Answers

Answered by divyaprakash1281
0

Answer:

Factoring a2-14a-15

The first term is, a2 its coefficient is 1 .

The middle term is, -14a its coefficient is -14 .

The last term, "the constant", is -15

Step-1 : Multiply the coefficient of the first term by the constant 1 • -15 = -15

Step-2 : Find two factors of -15 whose sum equals the coefficient of the middle term, which is -14 .

-15 + 1 = -14 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -15 and 1

a2 - 15a + 1a - 15

Step-4 : Add up the first 2 terms, pulling out like factors :

a • (a-15)

Add up the last 2 terms, pulling out common factors :

1 • (a-15)

Step-5 : Add up the four terms of step 4 :

(a+1) • (a-15)

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