Factorise a^2-23a+112
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Answered by
10
a^2 -23a+112
=a^2- 16a-7a+112
=a(a-16)-7(a-16)
=(a-7)(a-16)
a=7 or a=16
=a^2- 16a-7a+112
=a(a-16)-7(a-16)
=(a-7)(a-16)
a=7 or a=16
Answered by
3
a^2-23a+112
=a^2-16a-7a+112
=a(a-16)-7(a-16)
therefore (a-16)(a-7) is factor of a^2-23a+112
=a^2-16a-7a+112
=a(a-16)-7(a-16)
therefore (a-16)(a-7) is factor of a^2-23a+112
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