Factorise- (a 2 - 2a) 2 -23(a 2 -2a)+120
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Answer:
(a-5)(a+3)(a-4)(a+2)
Step-by-step explanation:
P(a)=(a2-2a)² - 23(a²-2a) +120
.. Let a²-2a be x
=>(a2-2a) 2-23(a²-2a) +120
x2-23x+120 [splitting the Middle term) x²-8x-15x+120
= x(x-8) -15(x-8)
= (x-15) (x-8)
=> (a2-2a -15) (a²-2a-8)
So= P(a) =(a2-2a-15) (a2-2a-8).
=(a-5) (a+3) (a-4) (a+2) by factorising the two factors.
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