Question

factorise (a^2-2a)-23(a^2-2a)+120​

Answer 1

Answer:

Step-by-step explanation:

(a^2-2a)*(-22)+120

Then we can take common 2

But really it can not

Answer 2

P(a) = (a² - 2 a)² - 23 (a² - 2 a) + 120 

        = x² - 23 x + 120

x = a² - 2 a 

120 = 15 * 8           15 + 8 = 23

then   x² - 15 x - 8 x + 120

           (x - 15) x - 8 (x - 15)

           (x - 15) ( x - 8)

so  

P(a) = ( a² - 2a -15) (a² - 2a - 8)

              = (a - 5) (a + 3) (a - 4) (a + 2)

by factorizing the two factors.

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