Math, asked by Rathore246yashwani, 9 months ago

factorise (a^2+3a)^2-5(a^2+3a)-b(a^2+3a)+5b

Answers

Answered by harshitaczone9

1

Step-by-step explanation:

(a^2+3a)^2-5(a^2+3a)-b(a^2+3a)+5b

(4a^+6a^)^-10a^-15a-2a^b-3ab +5b

16a^+36a^-10a^-15a-2a^b-3ab+5b

52a^-10a^-15a-2a^b-3ab+5b

42a^-15a+5b-a

42a^-16a+5b

2(21a-8)+5b

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