Question

factorise a^2 + 4b^2 + c^2 + 4ab + 4bc + 2ca​

Answer 1

Step-by-step explanation:

${a}^{2} + {2b}^{2} + {c}^{2} + 2a \times 2b + 2 \times 2b \times c + 2ca$

${(a + 2b + c)}^{2}$

answer is

$(a + 2b + c) \times (a + 2b + c)$