factorise: a^2+5a-104.
Answers
Answer:
1.1 Factoring a2-5a-104
The first term is, a2 its coefficient is 1 .
The middle term is, -5a its coefficient is -5 .
The last term, "the constant", is -104
Step-1 : Multiply the coefficient of the first term by the constant 1 • -104 = -104
Step-2 : Find two factors of -104 whose sum equals the coefficient of the middle term, which is -5 .
-104 + 1 = -103
-52 + 2 = -50
-26 + 4 = -22
-13 + 8 = -5 That's it
Step-3 : Rewrite the polynomial splitting the middle term using thetwo factors found in step 2 above, -13 and 8
a2 - 13a + 8a - 104
Step-4 : Add up the first 2 terms, pulling out like factors :
a • (a-13)
Add up the last 2 terms, pulling out common factors :
8 • (a-13)
Step-5 : Add up the four terms of step 4 :
(a+8) • (a-13)
Which is the desired factorization
Final result :
(a + 8) • (a - 13)