Question

factorise a^2-6ab+12bc-4c^2

Answer 1

This is how you factor it out
a(a-6b)+4c(3b-c)

Answer 2

Answer:

Given, a2 – 6ab + 12bc – 4c2

⇒ a2 – 4c2 – 6ab + 12bc

⇒ (a2 – (2c)2) – 6b(a – 2c)

[Since, from the identity III we know that, (x2 – y2) = (x – y)(x + y)]

⇒ (a + 2c)(a – 2c) – 6b(a – 2c)

⇒ (a – 2c)(a + 2c – 6b)