Question

Factorise a ²+ac+bc-b²​

Answer 1

Answer:

Hope it helps :)

Step-by-step explanation:

$=a^2+ac-b^2+bc\\\\=a(a+c)-b(b+c)$

Answer 2

Answer:

a^2+ac+bc-b^2

a^2-b^2+ac+bc

(a*a-b*b)+(a*c+b*c)

1(a-b)+c(a-b) because -*+=minus

(1+c)(a-b)