Question

factorise: a^2 +b^2+2ab-c^2​

Answer 1

Answer:

$= > (a + b + c)( a+b -c )$

Step-by-step explanation:

$since \: x {}^{2} + 2xy + y {}^{2} = (x + y) {}^{2}$

$therefore \: a {}^{2} + b {}^{2} + 2ab - c {}^{2} = \\ (a + b) {}^{2} - c {}^{2}$

$we \: all \: know \: that \: x {}^{2} - y {}^{2} = \\ (x + y)(x - y)$

$therefore \: given \: expression = > \\ (a + b) {}^{2} - c {}^{2}$

$= ((a + b) + c)((a + b) - c)$

$that \: is= (a + b +c )( a+ b - c)$