Question

Factorise : a^2-b^2+2bc-c^2

Answer 1

a^2-b^2+2bc-c^2
=a^2-(b^2-2bc+c^2)
=a^2-(b-c)^2
=(a+b-c)[a-(b-c)]
=(a+b-c)(a-b+c)

Answer 2

Solution ●●●●
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$= {a}^{2} - ( {b}^{2} - 2.b.c + {c}^{2} ) \\ \\ = ({a})^{2} - ( {b - c})^{2} \\ \\ = (a + b - c)[a - (b - c)] \\ \\ = (a + b - c)(a - b + c)$
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