Question

factorise :a^2+b^2+2bc-c^2

Answer 1

the answer is (a-b)²

Answer 2

нєу υѕєя,

${a}^{2} - {b}^{2} + 2bc - {c}^{2} = {a}^{2} - ( {b}^{2} - 2bc + {c}^{2} \\ = {a}^{2} - ( {b - c)}^{2} \\ = (a - (b - c))(a + (b - c)) \\ = (using \: identity \: \: \: \: {a}^{2} - {b}^{2} \\ = (a - b)(a + b)) \\ = (a - b - c)(a + b - c) \\ hence \: \: \: \: {a}^{2} - {b}^{2} + 2bc - {c}^{2} \\ = (a - b - c)(a + b - c)$
ι нσρє тнιѕ нєℓρѕ уσυ!
@vaibhav246