Factorise: (a^2-b^2)c+(b^2-c^2)a
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4
a^2c-b^2c+b^2a-c^2a
a^2c-c^2a-b^2c+b^2a
ac(a-c) +b^2(-c+a)
ac(a-c) + b^2 (a-c)
(a-c)(ac+b^2)
a^2c-c^2a-b^2c+b^2a
ac(a-c) +b^2(-c+a)
ac(a-c) + b^2 (a-c)
(a-c)(ac+b^2)
Answered by
1
(a^2-b^2)c+(b^2-c^2)a
=a^2c-b^2c+ab^2-ac^2
=ab^2+a^2c-b^2c-ac^2
=a(b^2+ac)-c(b^2+ac)
=(b^2+ac)(a -c) answer
=a^2c-b^2c+ab^2-ac^2
=ab^2+a^2c-b^2c-ac^2
=a(b^2+ac)-c(b^2+ac)
=(b^2+ac)(a -c) answer
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