Question

factorise a^2-(b-c)^2
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Answer 1

Answer:

a²-(b-c)² = (a+b-c)(a-b+c)

Explanation:

Factorising a²-(b-c)²

we know the algebraic identity:

\boxed {x^{2}-y^{2}=(x+y)(x-y)}

x

2

−y

2

=(x+y)(x−y)

= [a+(b-c)][a-(b-c)]

= (a+b-c)(a-b+c)

Therefore,

a²-(b-c)² = (a+b-c)(a-b+c)

Answer 2

Answer:

(a+b-c)(a-b+c)

Explanation:

a²-b²=(a+b)(a-b)

where a=a and b=b-c